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Find the point on the x-axis which is equidistant from (2, – 5) and (- 2, 9).Q.7

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Give me the best solution of coordinate geometry of class 10  . How i solve this question easily this is very important question of this chapter.  Find the point on the x-axis which is equidistant from (2, – 5) and (- 2, 9)

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  1. To find a point on x-axis. Therefore, its y-coordinate will be 0. Let the point on x-axis be (x,0).

    Consider A = (x, 0); B = (2, – 5) and C = (- 2, 9).

    NCERT Solutions for Class 10 Chapter 7-10

    Simplify the above equation,

    Remove square root by taking square both the sides, we get

    (2 – x)+ 25 = (-2 – x)+ 81

    x+ 4 – 4x + 25 = x+ 4 + 4x + 81

    8x = 25 – 81 = -56

    x = -7

    Therefore, the point is (- 7, 0).

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