Give me the best solution of coordinate geometry of class 10 . How i solve this question easily this is very important question of this chapter. Find the point on the x-axis which is equidistant from (2, – 5) and (- 2, 9)
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To find a point on x-axis. Therefore, its y-coordinate will be 0. Let the point on x-axis be (x,0).
Consider A = (x, 0); B = (2, – 5) and C = (- 2, 9).
Simplify the above equation,
Remove square root by taking square both the sides, we get
(2 – x)2 + 25 = (-2 – x)2 + 81
x2 + 4 – 4x + 25 = x2 + 4 + 4x + 81
8x = 25 – 81 = -56
x = -7
Therefore, the point is (- 7, 0).