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## . In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see Fig. 7.23). Show that:(ii) DBC is a right angle. (iii) ΔDBC ΔACB (iv) CM = ½ AB. Q.8(2),(3),(4)

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Find this important question of ncert class 9th of chapter triangles .Sir please help me to find out the easiest ...Read more

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## In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see Fig. 7.23). Show that: (i) ΔAMC ΔBMD .Q.8(1)

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What is  the ncert class 9th question of chapter triangles of exercise 7.1 question number 8(1). Please give me the ...Read more

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## AB is a line segment and P is its mid-point. D and E are points on the same side of AB such that BAD = ABE and EPA = DPB (see Fig. 7.22). Show that (i) ΔDAP ΔEBP (ii) AD = BE . Q.7

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Sir please help me to solve the ncert class 9th solution of chapter triangles.How I solve this question of exercise ...Read more

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## In Fig. 7.21, AC = AE, AB = AD and BAD = EAC. Show that BC = DE. Q.6

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This is very important question of ncert class 9th of chapter triangles. How I solve the best solution of exercise ...Read more

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## Line l is the bisector of an angle A and B is any point on l. BP and BQ are perpendiculars from B to the arms of A (see Fig. 7.20). Show that: (i) ΔAPB ΔAQB (ii) BP = BQ or B is equidistant from the arms of A. Q.5

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Today i am solving this important question of triangles its very hard to solve .Find this important question of ncert ...Read more

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## l and m are two parallel lines intersected by another pair of parallel lines p and q (see Fig. 7.19). Show that ΔABC ΔCDA. Q.4

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Find the simplest solution of ncert class 9th solution of triangles of exercise 7.1 question number 4. Sir please help ...Read more

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## AD and BC are equal perpendiculars to a line segment AB (see Fig. 7.18). Show that CD bisects AB.Q.3

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Today I am solving the ncert class 9th solution of chapter triangles.Find the best solution of exercise 7.1 question number ...Read more

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## ABCD is a quadrilateral in which AD = BC and DAB = CBA (see Fig. 7.17). Prove that (i) ΔABD ΔBAC (ii) BD = AC (iii) ABD = BAC. Q.2

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Sir please help me to solve the ncert class 9th solution of chapter triangles.How I solve this question of exercise ...Read more

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## In quadrilateral ACBD, AC = AD and AB bisect A (see Fig. 7.16). Show that ΔABC ΔABD. What can you say about BC and BD? Q.1

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What is  the ncert class 9th question of chapter triangles of exercise 7.1 question number 1. Please give me the ...Read more

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## Find a relation between x and y such that the point (x, y) is equidistant from the point (3, 6) and (- 3, 4). Q.10

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Give me the best solution of coordinate geometry of  ncert 10 class . How i solve this question fast and ...Read more