One of the most important and exam oriented question from trigonometric identities in which we have to find the value of cosec²(90°-θ)-tan²θ
Kindly give me a detailed solution of this question
RS Aggarwal, Class 10, chapter 13C, question no 8
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cosec²(90−θ)−tan²θ
=[cosec(90−θ)]²−tan²θ
=sec²θ−tan²θ [∵cosec(90−θ)=secθ]
=1.