This question is from trigonometry topic – trigonometric identities in which we have to prove that (secθ-tanθ)/(secθ+tanθ) = cos²θ/(1+sinθ)² RS Aggarwal, class 10, chapter 13A, question no 20(ii).

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This question is from trigonometry topic – trigonometric identities in which we have to prove that (1-tan²θ)/1+tan²θ) = cos²θ-sin²θ RS Aggarwal, class 10, chapter 13A, question no 18(i)

This question is from trigonometry topic – trigonometric identities in which we have been asked to prove that (1+tan²θ)(1+cot²θ) = 1/(sin²θ-sin^4θ) RS Aggarwal, Class 10, chapter 13A, question no 15

This question is from trigonometry topic trigonometric identities in which we have to prove that cos²θ/(1-tanθ) + sin³θ/(sinθ-cosθ) = 1+sinθcosθ RS Aggarwal, Class 10, chapter 13A, question no 13.

This question is from trigonometry topic trigonometric identities in which we have to prove that 1 + tan²θ(1+secθ) = secθ RS Aggarwal, class 10, chapter 13A, question no 8(ii)

This question is from trigonometry topic – trigonometric identities in which we have to prove that sin²θ + 1/(1+tan²θ) = 1 RS Aggarwal, Class 10, Chapter 13A, question no 3(i)

This question is from trigonometry topic trigonometric identities in which we have been asked to show that (1-cos²θ)sec²θ=tan²θ RS Aggarwal, Class 10, chapter 13A, question no 2(iii).

This question is from trigonometry topic- trigonometric ratios on complementary angles in which we have been asked to prove that cos15° cos35° cosec55° cos60° cosec75° = 2 RS Aggarwal, Class 10, chapter 12, question no 6(iii)

This question is from trigonometry topic – trigonometric ratios on complementary angles in which we have been asked to prove that [sec(90°-θ) cosecθ – tan(90°-θ) cotθ + cos²25° + cos²65°]/3tan27°tan63° = 2/3 RS Aggarwal, Class 10, Chapter 12, question no 5(vi)

This question is from trigonometry topic – trigonometric ratios on complementary angles in which we have to prove that 7cos55°/3sin35° – [4(cos70°Cosec20°)]/3(tan5°tan25°tan45°tan65°tan85°) = 1 RS Aggarwal, class 10, chapter 12, question no 4(v).