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3. In fig. 5.37, find tan P and cot R. Is tan P = cot R?

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Class 10th cbse rd sharma trigonometric identites

 

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  1. Solution:

    R D Sharma Solutions For Class 10 Maths Chapter 5 Trigonometric Ratios ex 5.1 - 3

    By using Pythagoras theorem in △PQR, we have

    PR2 = PQ2 + QR2

    Putting the length of given side PR and PQ in the above equation,

    132 = 122 + QR2

    QR2 = 132 – 122

    QR2 = 169 – 144

    QR2 = 25

    QR = √25 = 5

    By definition,

    tan P = Perpendicular side opposite to P/ Base side adjacent to angle P

    tan P = QR/PQ

    tan P = 5/12 ………. (1)

    And,

    cot R= Base/Perpendicular

    cot R= QR/PQ

    cot R= 5/12 …. (2)

    When comparing equation (1) and (2), we can see that R.H.S of both the equation is equal.

    Therefore, L.H.S of both equations should also be equal.

    ∴ tan P = cot R

    Yes, tan P = cot R = 5/12

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