0 deepaksoniGuru Asked: March 17, 20212021-03-17T23:53:24+05:30 2021-03-17T23:53:24+05:30In: ICSE Three numbers are in the ratio 1/2: 1/3: ¼. If the sum of their squares is 244, find the numbers 0 It is a question from ML aggarwal, class 10th, chapter 7, ratio and proportion, Avichal publication In this question we have a total sum and ratio in which we have to divide the sum. Question 17 ml aggarwal solutionratio and proportion Share Facebook 1 Answer Voted Oldest Recent AAREKH Guru 2021-03-24T13:53:20+05:30Added an answer on March 24, 2021 at 1:53 pm Solution: It is given that Ratio of three numbers = 1/2: 1/3: 1/4 = (6: 4: 3)/ 12 = 6: 4: 3 Consider first number = 6x Second number = 4x Third number = 3x So based on the condition (6x)^{2} + (4x)^{2} + (3x)^{2} = 244 36x^{2} + 16x^{2} + 9x^{2} = 244 So we get 61x^{2} = 244 x^{2} = 244/61 = 4 = 2^{2} x = 2 Here First number = 6x = 6 × 2 = 12 Second number = 4x = 4 × 2 = 8 Third number = 3x = 3 × 2 = 6 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions Question 16. In the given figure, chords AB and CD of the circle are produced to meet at ... Question 15. (a) Prove that a cyclic parallelogram is a rectangle. (b) Prove that a cyclic rhombus is ... Question 14. In the given figure, ABC is an isosceles triangle in which AB = AC and circle ... Ques 13(b) In the figure (ii) given below, SP is the bisector of ∠RPT and PQRS is a ... Question 13. (a) In the figure (i) given below, ED and BC are two parallel chords of the ...

Solution:It is given that

Ratio of three numbers = 1/2: 1/3: 1/4

= (6: 4: 3)/ 12

= 6: 4: 3

Consider first number = 6x

Second number = 4x

Third number = 3x

So based on the condition

(6x)

^{2}+ (4x)^{2}+ (3x)^{2}= 24436x

^{2}+ 16x^{2}+ 9x^{2}= 244So we get

61x

^{2}= 244x

^{2}= 244/61 = 4 = 2^{2}x = 2

Here

First number = 6x = 6 × 2 = 12

Second number = 4x = 4 × 2 = 8

Third number = 3x = 3 × 2 = 6