How i solve the question of 10th math of exercise 3.6 in easy way. This is an important question of 10th class Solve the following pairs of equations by reducing them to a pair of linear equations: (ii) 2/√x + 3/√y = 2 4/√x + 9/√y = -1
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Solve the following pairs of equations by reducing them to a pair of linear equations: (ii) 2/√x + 3/√y = 2 4/√x + 9/√y = -1 Q.1(2)
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Substituting 1/√x = m and 1/√y = n in the given equations, we get
2m + 3n = 2 ………………………..(i)
4m – 9n = -1 ………………………(ii)
Multiplying equation (i) by 3, we get
6m + 9n = 6 ………………….…..(iii)
Adding equation (ii) and (iii), we get
10m = 5
m = 1/2…………………………….…(iv)
Now by putting the value of ‘m’ in equation (i), we get
2×1/2 + 3n = 2
3n = 1
n = 1/3
m =1/√x
½ = 1/√x
x = 4
n = 1/√y
1/3 = 1/√y
y = 9
Hence, x = 4 and y = 9