What is the solution of the question of class 10th ncert book of Probability chapter of optional exercise 15.2 of question no.2, give me the best solution for this chapter A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball is double that of a red ball, determine the number of blue balls in the bag.

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# A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball is double that of a red ball, determine the number of blue balls in the bag. Q.3

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It is given that the total number of red balls = 5

Let the total number of blue balls = x

So, the total no. of balls = x+5

P(E) = (Number of favourable outcomes/ Total number of outcomes)

âˆ´ P (drawing a blue ball) = [x/(x+5)] â€”â€”â€“(i)

Similarly,

P (drawing a red ball) = [5/(x+5)] â€”â€”â€“(i)

From equation (i) and (ii)

x = 10

So, the total number of blue balls = 10