How i solve the question of 10th math of exercise 3.6 in easy way. This is an important question of 10th class Solve the following pairs of equations by reducing them to a pair of linear equations: (ii) 2/√x + 3/√y = 2 4/√x + 9/√y = -1

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# Solve the following pairs of equations by reducing them to a pair of linear equations: (ii) 2/√x + 3/√y = 2 4/√x + 9/√y = -1 Q.1(2)

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Substituting 1/√x = m and 1/√y = n in the given equations, we get

2m + 3n = 2 ………………………..(i)

4m – 9n = -1 ………………………(ii)

Multiplying equation (i) by 3, we get

6m + 9n = 6 ………………….…..(iii)

Adding equation (ii) and (iii), we get

10m = 5

m = 1/2…………………………….…(iv)

Now by putting the value of ‘m’ in equation (i), we get

2×1/2 + 3n = 2

3n = 1

n = 1/3

m =1/√x

½ = 1/√x

x = 4

n = 1/√y

1/3 = 1/√y

y = 9

Hence, x = 4 and y = 9