This is an arithmetic progression based question from Chapter name- Arithmetic Progression
Chapter number- 9
Exercise – 9.6
In this question we have been given that there be an A.P.
first term a and common difference d.
Also, If an denotes its nth term and Sn is the sum of first n terms
Now we have to find n and d if a = 8, an = 62 and Sn = 210
CBSE DHANPAT RAI PUBLICATIONS
Understanding CBSE Mathematics
Class :- 10th
Question no 56(v)
Given A.P. has a = 8, an = 62 and Sn = 210.
Now by using the formula of sum of n terms of an A.P.
Sn = n[a + an] / 2
So,
=> 210 = n[8 + 62] / 2
=> 70n = 420
=> n = 6
By using the formula of nth term of an A.P.
an = a + (n – 1)d
So,
=> 62 = 8 + (6 – 1)d
=> 5d = 54
=> d = 54/5
Hence, the value of n is 6 and d is 54/5.