This is the basic and conceptual question from Chapter name- Arithmetic Progression
Chapter number- 9
Exercise 9.6
In this question we have been given that there be an A.P.
first term a and common difference d.
Also, If an denotes its nth term and Sn is the sum of first n terms,
Now we have to find d, if a = 3, n = 8 and Sn = 192
CBSE DHANPAT RAI publications
Class:- 10th
Solutions of CBSE Mathematics
Question 56(iii)
Given A.P. has a = 3, n = 8 and Sn = 192.
Now by using the formula of the sum of n terms of an A.P.
Sn = n[2a +(n – 1)d] / 2
So,
=> 192 = 8[2(3) + (8 – 1)d] / 2
=> 4[6+7d] = 192
=> 6+7d = 48
=> 7d = 42
=> d = 6
Hence, the value of d is 6.