This is the basic and conceptual question from Chapter name- Arithmetic Progression

Chapter number- 9

Exercise 9.4

In this question we have been given an arithmetic progression. And we have to find its 18th term.

CBSE DHANPAT RAI publications

Class:- 10th

Understanding CBSE Mathematics

Question 1(ii)

Given that,

A.P. is √2, 3√2, 5√2, …….

First term (a) = √2,

Common difference = Second term – First term

d = 3√2 – √2 = 2√2

As we know that, to find nth term in an A.P = a + (n – 1)d

Therefore, 18th term of A. P. = √2 + (18 – 1)2√2

= √2 + 17.2√2 = √2 (1+34) = 35√2