This is the basic and conceptual question from Chapter name- Arithmetic Progression
Chapter number- 9
Exercise 9.4
In this question we have been given an arithmetic progression. And we have to find its 18th term.
CBSE DHANPAT RAI publications
Class:- 10th
Understanding CBSE Mathematics
Question 1(ii)
Given that,
A.P. is √2, 3√2, 5√2, …….
First term (a) = √2,
Common difference = Second term – First term
d = 3√2 – √2 = 2√2
As we know that, to find nth term in an A.P = a + (n – 1)d
Therefore, 18th term of A. P. = √2 + (18 – 1)2√2
= √2 + 17.2√2 = √2 (1+34) = 35√2