The chapter of Triangles of class 10th math of exercise 6.2 , how i solve this problem. It is very important. Yesterday i was doing this question but i was not able to do this question In the figure, DE||OQ and DF||OR, show that EF||QR.
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Given,
In ΔPQO, DE || OQ
So by using Basic Proportionality Theorem,
PD/DO = PE/EQ……………… ..(i)
Again given, in ΔPOR, DF || OR,
So by using Basic Proportionality Theorem,
PD/DO = PF/FR………………… (ii)
From equation (i) and (ii), we get,
PE/EQ = PF/FR
Therefore, by converse of Basic Proportionality Theorem,
EF || QR, in ΔPQR.