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In the figure, DE||OQ and DF||OR, show that EF||QR. Q.5

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The chapter of Triangles of class 10th math of exercise 6.2 , how i solve this problem. It is very important. Yesterday i was doing this question but i was not able to do this question In the figure, DE||OQ and DF||OR, show that EF||QR.

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  1. Given,

    In ΔPQO, DE || OQ

    So by using Basic Proportionality Theorem,

    PD/DO = PE/EQ……………… ..(i)

    Again given, in ΔPOR, DF || OR,

    So by using Basic Proportionality Theorem,

    PD/DO = PF/FR………………… (ii)

    From equation (i) and (ii), we get,

    PE/EQ = PF/FR

    Therefore, by converse of Basic Proportionality Theorem,

    EF || QR, in ΔPQR.

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