In the figure, DE||OQ and DF||OR, show that EF||QR. Q.5

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The chapter of Triangles of class 10th math of exercise 6.2 , how i solve this problem. It is very important. Yesterday i was doing this question but i was not able to do this question In the figure, DE||OQ and DF||OR, show that EF||QR.

Given,

In ΔPQO, DE || OQ

So by using Basic Proportionality Theorem,

PD/DO = PE/EQ………………

..(i)Again given, in ΔPOR, DF || OR,

So by using Basic Proportionality Theorem,

PD/DO = PF/FR…………………

(ii)From equation

(i)and(ii), we get,PE/EQ = PF/FR

Therefore, by converse of Basic Proportionality Theorem,

EF || QR, in ΔPQR.