I want to know the best answer of the question from Lines and Angles chapter of class 9th ncert math. The question from exercise 6.2of math. Give me the easy way for solving this question of 5 In Fig. 6.32, if AB CD, APQ = 50° and PRD = 127°, find x and y.
From the diagram,
APQ = PQR (Alternate interior angles)
Now, putting the value of APQ = 50° and PQR = x we get,
x = 50°
Also,
APR = PRD (Alternate interior angles)
Or, APR = 127° (As it is given that PRD = 127°)
We know that
APR = APQ+QPR
Now, putting values of QPR = y and APR = 127° we get,
127° = 50°+ y
Or, y = 77°
Thus, the values of x and y are calculated as:
x = 50° and y = 77°