I want to know the best answer of the question from Lines and Angles chapter of class 9^{th} ncert math. The question from exercise 6.2of math. Give me the easy way for solving this question of 5 In Fig. 6.32, if AB CD, APQ = 50° and PRD = 127°, find x and y.

Share

From the diagram,

APQ = PQR (Alternate interior angles)

Now, putting the value of APQ = 50° and PQR = x we get,

x = 50°

Also,

APR = PRD (Alternate interior angles)

Or, APR = 127° (As it is given that PRD = 127°)

We know that

APR = APQ+QPR

Now, putting values of QPR = y and APR = 127° we get,

127° = 50°+ y

Or, y = 77°

Thus, the values of x and y are calculated as:

x = 50° and y = 77°