1 AnilSinghBoraGuru Asked: July 14, 20212021-07-14T21:27:38+05:30 2021-07-14T21:27:38+05:30In: NCERT Class 10th Maths Find two numbers whose sum is 27 and product is 182. Q.3 1 How i solve the question of exercise 4.2 of class 10th of 3rd question by easy way. Because it somewhat lengthy question Find two numbers whose sum is 27 and product is 182. best solutionexercise 4.2 ncertncert class 10th solutionquadratic equation ncert Share Facebook 2 Answers Voted Oldest Recent bhagwansingh Guru 2021-07-14T22:07:13+05:30Added an answer on July 14, 2021 at 10:07 pm Let us say, first number be x and the second number is 27 – x. Therefore, the product of two numbers x(27 – x) = 182 ⇒ x^{2} – 27x – 182 = 0 ⇒ x^{2} – 13x – 14x + 182 = 0 ⇒ x(x – 13) -14(x – 13) = 0 ⇒ (x – 13)(x -14) = 0 Thus, either, x = -13 = 0 or x – 14 = 0 ⇒ x = 13 or x = 14 Therefore, if first number = 13, then second number = 27 – 13 = 14 And if first number = 14, then second number = 27 – 14 = 13 Hence, the numbers are 13 and 14. 2 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Deepak Bora Newbie 2022-02-21T14:55:42+05:30Added an answer on February 21, 2022 at 2:55 pm This is the video solution. I hope this will help you. Tell me your comment!!!!! 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions Find the value of k, if x = 2, y = 1 is a solution of the equation ... Check which of the following are solutions of the equation x–2y = 4 and which are not:(v) (1, ... Check which of the following are solutions of the equation x–2y = 4 and which are not:(iv) (√2, ... Check which of the following are solutions of the equation x–2y = 4 and which are not: (iii) ... Check which of the following are solutions of the equation x–2y = 4 and which are not:(ii) (2, ...

Let us say, first number be x and the second number is 27 – x.

Therefore, the product of two numbers

x(27 – x) = 182

⇒ x

^{2}– 27x – 182 = 0⇒ x

^{2}– 13x – 14x + 182 = 0⇒ x(x – 13) -14(x – 13) = 0

⇒ (x – 13)(x -14) = 0

Thus, either, x = -13 = 0 or x – 14 = 0

⇒ x = 13 or x = 14

Therefore, if first number = 13, then second number = 27 – 13 = 14

And if first number = 14, then second number = 27 – 14 = 13

Hence, the numbers are 13 and 14.

This is the video solution. I hope this will help you. Tell me your comment!!!!!