This question is taken from linear equations in two variables in which we have given two equations kx+3y=k-3, 12x+ky=k for which the given equations has no solution and also asked to find the value of k

Kindly give me a detailed solution of this question

RS Aggarwal, Class 10, chapter 3D, question no 30

## The equations are

⇒kx+3y−k+3=0

⇒a1=k,b1=3,c1=3

⇒12x+ky−k=0

⇒a2=12,b2=k,c2=−k

The given system of equations has no solution

⇒a1/a2=b1/b2≠c1/c2

So we are considering

⇒a1/b1=a2/b2

⇒k/12=3/k

⇒k²=36

⇒k=6