This question is taken from linear equations in two variables in which we have given two equations kx+3y=k-3, 12x+ky=k for which the given equations has no solution and also asked to find the value of k
Kindly give me a detailed solution of this question
RS Aggarwal, Class 10, chapter 3D, question no 30
The equations are
⇒kx+3y−k+3=0
⇒a1=k,b1=3,c1=3
⇒12x+ky−k=0
⇒a2=12,b2=k,c2=−k
The given system of equations has no solution
⇒a1/a2=b1/b2≠c1/c2
So we are considering
⇒a1/b1=a2/b2
⇒k/12=3/k
⇒k²=36
⇒k=6