This question is taken from linear equations in two variables in which we have given two equations kx+3y=k-3, 12x+ky=k for which the given equations has no solution and also asked to find the value of k
Kindly give me a detailed solution of this question
RS Aggarwal, Class 10, chapter 3D, question no 30
The equations are
⇒kx+3y−k+3=0
⇒a1​=k,b1​=3,c1​=3
⇒12x+ky−k=0
⇒a2​=12,b2​=k,c2​=−k
The  given  system  of  equations  has  no  solution
⇒a1/a2​​=​b1/b2​​≠​c1/c2​​
So we are considering
⇒a1​​/b1=a2/b2​​
⇒k/12​=3/k
​⇒k²=36
⇒k=6