What is the best solution for the solving the question of arithmetic progressions of exercise 5.3 of class 10th math, Find the sum of the following APs. (i) 2, 7, 12 ,…., to 10 terms.
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Given, 2, 7, 12 ,…, to 10 terms
For this A.P.,
first term, a = 2
And common difference, d = a2 − a1 = 7−2 = 5
n = 10
We know that, the formula for sum of nth term in AP series is,
Sn = n/2 [2a +(n-1)d]
S10 = 10/2 [2(2)+(10 -1)×5]
= 5[4+(9)×(5)]
= 5 × 49 = 245