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Find a relation between x and y such that the point (x, y) is equidistant from the point (3, 6) and (- 3, 4). Q.10

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Give me the best solution of coordinate geometry of  ncert 10 class . How i solve this question fast and easy way  please help me to solve this important question. Find a relation between x and y such that the point (x, y) is equidistant from the point (3, 6) and (- 3, 4).

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  1. Point (x, y) is equidistant from (3, 6) and ( – 3, 4).

    NCERT Solutions for Class 10 Chapter 7-14

    Squaring both sides, (x – 3)2+(y – 6)2 = (x + 3)2 +(y – 4)2

    x+ 9 – 6x + y2+ 36 – 12y = x+ 9 + 6x + y+16 – 8y

    36 – 16 = 6x + 6x + 12y – 8y

    20 = 12x + 4y

    3x + y = 5

    3x + y – 5 = 0

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