Today i am solving the introduction of trigonometry of class 10 ncert . How i solve the question of exercise 8.2 question no.1(3) . Give me the best and easy solution of this question.Evaluate the following: (iii) cos 45°/(sec 30°+cosec 30°)
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cos 45°/(sec 30°+cosec 30°)
We know that,
cos 45° = 1/√2
sec 30° = 2/√3
cosec 30° = 2
Substitute the values, we get
Now, multiply both the numerator and denominator by √2 , we get
Therefore, cos 45°/(sec 30°+cosec 30°) = (3√2 – √6)/8