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Evaluate the following: (iii) cos 45°/(sec 30°+cosec 30°) Q.1(3)

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Today i am solving the introduction of trigonometry of class 10 ncert . How i solve the question of exercise 8.2 question no.1(3) . Give me the best and easy solution of this question.Evaluate the following: (iii) cos 45°/(sec 30°+cosec 30°)

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  1. cos 45°/(sec 30°+cosec 30°)

    We know that,

    cos 45° = 1/√2

    sec 30° = 2/√3

    cosec 30° = 2

    Substitute the values, we get

    Ncert solutions class 10 chapter 8-5

    Now, multiply both the numerator and denominator by √2 , we get

    Ncert solutions class 10 chapter 8-6

    Therefore, cos 45°/(sec 30°+cosec 30°) = (3√2 – √6)/8

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