Find the best method of the ncert class 10 chapter surface areas and volumes . In exercise 13.1 question number 3 is very tricky question i don’t understand the formula of this question please help me put the formula into the question also give the best solution of the question. A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same radius. The total height of the toy is 15.5 cm. Find the total surface area of the toy.
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A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same radius. The total height of the toy is 15.5 cm. Find the total surface area of the toy.Q.3
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The diagram is as follows:
Given that the radius of the cone and the hemisphere (r) = 3.5 cm or 7/2 cm
The total height of the toy is given as 15.5 cm.
So, the height of the cone (h) = 15.5-3.5 = 12 cm
∴ The curved surface area of cone = πrl
(22/7)×(7/2)×(25/2) = 275/2 cm2
Also, the curved surface area of the hemisphere = 2πr2
2×(22/7)×(7/2)2
= 77 cm2
Now, the Total surface area of the toy = CSA of cone + CSA of hemisphere
= (275/2)+77 cm2
= (275+154)/2 cm2
= 429/2 cm2 = 214.5cm2
So, the total surface area (TSA) of the toy is 214.5cm2