The best question of optional chapter of arithmetic progressions of exercise 5.4 of class 10th math, how i solve this question in easy way A small terrace at a football ground comprises of 15 steps each of which is 50 m long and built of solid concrete. Each step has a rise of 1 4 m and a tread of 1 2 m. (see Fig. 5.8). Calculate the total volume of concrete required to build the terrace. [Hint : Volume of concrete required to build the first step = ¼ ×1/2 ×50 m3.] Ncert solutions class 10 chapter 5-17

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# A small terrace at a football ground comprises of 15 steps each of which is 50 m long and built of solid concrete. Each step has a rise of 1 4 m and a tread of 1 2 m. (see Fig. 5.8). Calculate the total volume of concrete required to build the terrace. [Hint : Volume of concrete required to build the first step = ¼ ×1/2 ×50 m3.] Ncert solutions class 10 chapter 5-17 Q.5

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As we can see from the given figure, the first step is ½ m wide, 2

^{nd}step is 1m wide and 3^{rd}step is 3/2m wide. Thus we can understand that the width of step by ½ m each time when height is ¼ m. And also, given length of the steps is 50m all the time. So, the width of steps forms a series AP in such a way that;½ , 1, 3/2, 2, ……..

Volume of steps = Volume of Cuboid

= Length × Breadth Height

Now,

Volume of concrete required to build the first step = ¼ ×1/2 ×50 = 25/4

Volume of concrete required to build the second step =¼ ×1/×50 = 25/2

Volume of concrete required to build the second step = ¼ ×3/2 ×50 = 75/2

Now, we can see the volumes of concrete required to build the steps, are in AP series;

25/4 , 25/2 , 75/2 …..

Thus, applying the AP series concept,

First term, a = 25/4

Common difference, d = 25/2 – 25/4 = 25/4

As we know, the sum of n terms is;

S

_{n}= n/2[2a+(n-1)d] = 15/2(2×(25/4 )+(15/2 -1)25/4)Upon solving, we get,

S

_{n =}15/2 (100)S

_{n}750Hence, the total volume of concrete required to build the terrace is 750 m

^{3}.