What is the solution for class 10 ncert chapter surface areas and volumes . Find the best solution of the exercise 13.1 question number 5 give me the easiest and simplest solution of this question .A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid.
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A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid. Q.5
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The diagram is as follows:
Now, the diameter of hemisphere = Edge of the cube = l
So, the radius of hemisphere = l/2
∴ The total surface area of solid = surface area of cube + CSA of hemisphere – Area of base of hemisphere
TSA of remaining solid = 6 (edge)2+2πr2-πr2
= 6l2 πr2
= 6l2+π(l/2)2
= 6l2+πl2/4
= l2/4(24+π) sq. units