What is the solution for class 10 ncert chapter surface areas and volumes . Find the best solution of the exercise 13.1 question number 5 give me the easiest and simplest solution of this question .A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid.

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# A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid. Q.5

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The diagram is as follows:

Now, the diameter of hemisphere = Edge of the cube = l

So, the radius of hemisphere = l/2

âˆ´ The total surface area of solid = surface area of cube + CSA of hemisphere â€“ Area of base of hemisphere

TSA of remaining solid = 6 (edge)

^{2}+2Ï€r^{2}-Ï€r^{2}= 6l

^{2}Â Ï€r^{2}= 6l

^{2}+Ï€(l/2)^{2}= 6l

^{2}+Ï€l^{2}/4= l

^{2}/4(24+Ï€) sq. units