The following Problem is from Arithmetic Progression in NCERT, Excercise 5.1 question no. 2 (iii). In this question you have to derive the 1st four terms of the A.P which will be formed by the above information.
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Solution:
a = 4, d = – 3
Let the A.P be a1, a2, a3, a4, a5 …
a1 = a = 4
a2 = a1+d = 4-3 = 1
a3 = a2+d = 1-3 = – 2
a4 = a3+d = -2-3 = – 5
First four terms of A.P. are 4, 1, – 2 and – 5.