The following Problem is from Arithmetic Progression in NCERT, Excercise 5.1 question no. 2 (iii). In this question you have to derive the 1st four terms of the A.P which will be formed by the above information.

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Solution:a= 4,d= – 3Let the A.P be

a_{1}, a_{2}, a_{3}, a_{4}, a_{5}…a_{1}=a= 4a_{2}=a_{1}+d= 4-3 = 1a_{3}=a_{2}+d= 1-3 = – 2a_{4}=a_{3}+d= -2-3 = – 5First four terms of A.P. are 4, 1, – 2 and – 5.