Sir please give me a detailed solution of this question as it is already asked in previous year paper of 2008 in which we have to find the value of (1+tan²θ)(1+sinθ)(1-sinθ) using trigonometric formulas
RS Aggarwal, Class 10, chapter 13C, question no 12
(1+tan²θ)(1+sinθ)(1−sinθ)
=sec²θ(1−sin²θ)
=sec²θ×cos²θ
=1/cos²θ×cos²θ
=1