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Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. How much area will it irrigate in 30 minutes, if 8 cm of standing water is needed? Q.8

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In chapter surface areas and volumes of ncert class 10 , please help me to solve the exercise 13.3 question number 8 . Find the best solution of this question also give me the easiest and simplest way to solve this tricky question .Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. How much area will it irrigate in 30 minutes, if 8 cm of standing water is needed?

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  1. It is given that the canal is the shape of a cuboid with dimensions as:

    Breadth (b) = 6 m and Height (h) = 1.5 m

    It is also given that

    The speed of canal = 10 km/hr

    Length of canal covered in 1 hour = 10 km

    Length of canal covered in 60 minutes = 10 km

    Length of canal covered in 1 min = (1/60)x10 km

    Length of canal covered in 30 min (l) = (30/60)x10 = 5km = 5000 m

    We know that the canal is cuboidal in shape. So,

    Volume of canal = lxbxh

    = 5000x6x1.5 m3

    = 45000 m3

    Now,

    Volume of water in canal = Volume of area irrigated

    = Area irrigated x Height

    So, Area irrigated = 56.25 hectares

    ∴ Volume of canal = lxbxh

    45000 = Area irrigatedx8 cm

    45000 = Area irrigated x (8/100)m

    Or, Area irrigated = 562500 m= 56.25 hectares.

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