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deepaksoni
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Asked: 2021-03-16T23:22:46+05:30 In:

Two years ago, a man’s age was three times the square of his daughter’s age. Three years hence, his age will be four times his daughter’s age. Find their present ages.

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This question has been taken from Book:- ML aggarwal, Avichal publication, class10th, quadratic equation in one variable, chapter 5, exercise 5.5
This is an important ques and asked in previous year question paper.
Two years ago, a man’s age was three times the square of his daughter’s age.

Three years hence, his age will be four times his daughter’s age.

Find their present ages.

Question no.44 , ML Aggarwal, chapter 5, exercise 5.5, quadratic equation in one variable, ICSE board,

icse boardml aggarwal solutionquadratic equation in one variable
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    1 Answer

    1. Guru

      Solution:
      2 years ago,
      Let the age of daughter = x
      age of man = 3x²
      then present age of daughter = x + 2
      and mean = 3x² + 2
      ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 5 Quadratic Equations in One Variable Ex 5.5 Q44.1

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