What is the ncert class 9th question of chapter triangles of exercise 7.3 question number 3(1). Please give me the simplest and easiest solution of this question , also give me the best solution of this question. Also find the best solution of this question.Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of ΔPQR (see Fig. 7.40). Show that: (i) ΔABM ΔPQN
Given parameters are:
AB = PQ,
BC = QR and
AM = PN
(i) ½ BC = BM and ½ QR = QN (Since AM and PN are medians)
Also, BC = QR
So, ½ BC = ½ QR
⇒ BM = QN
In ΔABM and ΔPQN,
AM = PN and AB = PQ (As given in the question)
BM = QN (Already proved)
∴ ΔABM ΔPQN by SSS congruency.