1 Deepak Bora Asked: July 10, 20202020-07-10T13:16:02+05:30 2020-07-10T13:16:02+05:30In: CBSE, ICSE Two different dice are tossed together. Find the probability of the sum of no’s appearing on two dice is 5. 1 This is a question in maths chapter probability and I can’t answer this please help?? dice questionprobability Share Facebook Related Questions Find the probability of having 53 Sundays in a leap year, and a non-leap year. 2 Answers Voted Oldest Recent Deepak Bora 2020-07-10T19:29:54+05:30Added an answer on July 10, 2020 at 7:29 pm P(sum=5) : The favourable outcomes ={(3,2),(1,4)} Number of favorable outcomes =2 ∴ Probability of getting a sum 5 =P(sum=5)=236=1/18 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Deepak Bora 2020-07-14T10:41:26+05:30Added an answer on July 14, 2020 at 10:41 am let s be the total number of sample space if two diced are rolled then the total number of sample space n(s)=6²=36 sample spaces when the sum on the dice is 5 n(B)= { (1,4),(2,3),(3,2),(4,1)} = 4 P(B)=n(B) / n(S) =4/36 =1/9 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment.

P(sum=5) :

The favourable outcomes ={(3,2),(1,4)}

Number of favorable outcomes =2

∴ Probability of getting a sum 5 =P(sum=5)=236=1/18

let s be the total number of sample space

if two diced are rolled then the total number of sample space n(s)=6²=36

sample spaces when the sum on the dice is 5

n(B)= { (1,4),(2,3),(3,2),(4,1)} = 4

P(B)=n(B) / n(S)

=4/36

=1/9