Today i am solving the ncert class 10 question of areas related to circles . Find the best solution of exercise 12.2 question number 14 . Give me the easiest and simplest solution of this question.Tick the correct solution in the following: Area of a sector of angle p (in degrees) of a circle with radius R is (A) p/180 × 2πR (B) p/180 × π R2 (C) p/360 × 2πR (D) p/720 × 2πR2.
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Tick the correct solution in the following: Area of a sector of angle p (in degrees) of a circle with radius R is (A) p/180 × 2πR (B) p/180 × π R2 (C) p/360 × 2πR (D) p/720 × 2πR2. Q.14
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The area of a sector = (θ/360°)×πr2
Given, θ = p
So, area of sector = p/360×πR2
Multiplying and dividing by 2 simultaneously,
= (p/360)×2/2×πR2
= (2p/720)×2πR2
So, option (D) is correct.