Find the simplest solution of ncert class 9th solution of linear equations in two variables of exercise 4.3 question number 1(4). Sir please help me to solve this question in a easiest and best way. Please help me to solve this question in a simplest method. Q.4
SonuNewbie
The taxi fare in a city is as follows: For the first kilometer, the fare is ₹8 and for the subsequent distance it is ₹5 per km. Taking the distance covered as x km and total fare as ₹ y, write a linear equation for this information, and draw its graph.Q.4
Share
Solution:
Given,
Total distance covered = x
Total fare = y
Fare for the first kilometer = 8 per km
Fare after the first 1km = 5 per km
If x is the total distance, then the distance after one km = (x-1)km
i.e., Fare after the first km = 5(x-1)
According to the question,
The total fare = Fare of first km+ fare after the first km
y = 8+5(x-1)
y = 8+5(x-1)
y = 8+5x – 5
y = 5x+3
Solving the equation,
When x = 0,
y = 5x+3
y = 5×0+3
y = 3
When y = 0,
y = 5x+3
o = 5x+3
5x = -3
x = -3/5
The points to be plotted are (0, 3) and (-3/5, 0)
