ICSE & CBSE Board Question Based on Arithmetic Progression of RS Aggarwal

Here you have to find the numbers of AP with the help of their given sum and their product.

This is the Question Number 3 Of Exercise 11 B of RS Aggarwal Solution.

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# The sum of three numbers in Ap is 27 and their Product is 405. Find the numbers.

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Let the three numbers in A.P is a−d,a,a+d

Sum of three numbers is 27

⟹a−d+a+a+d=27⟹a=9

Product is 405

⟹(9−d)(9)(9+d)=405

⟹81−d2=45⟹d2=36⟹d=±6

The numbers are 3,9,15