Home/ Questions/Q 512
In Process
Adv
Deepak Bora
  • 6
Newbie
Asked: 2020-07-30T21:31:19+05:30 In:

The Centre of a circle whose end points of a diameter are (-6, 3) and (6, 4) is

  • 6

CBSE 10th Class Mathematics

Past year question paper

Year 2020

SET 1, Code Number  – 30/2/1

Question Number –  3 [b]
circle problem
circle lies in 1st and 2nd quadrant

cbse class 10thlast year paperncert class 10th
Share

    1 Answer

    1. Newbie
      This answer was edited.

      Using the mid point formula coordinates of mid points are

       

      (x1 + x2) / 2 = X

      (y1 + y2) / 2 = Y

      Here

      x1 = 6, x2 = -6

      y1 = 3, y2 = 4

       

      ∴ (6 + (-6)) / 2 = 0

      (3 + 4) / 2 = 7/2

      Coordinates of Mid point will be

      (X,Y) = (0,(7/2))

      • 1
    Leave an answer

    Leave an answer

    Browse

    Choose from here the video type.

    Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

    Captcha Click on image to update the captcha.

    Related Questions

    Adv