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The Centre of a circle whose end points of a diameter are (-6, 3) and (6, 4) is

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CBSE 10th Class Mathematics

Past year question paper

Year 2020

SET 1, Code Number  – 30/2/1

Question Number –  3 [b]
circle problem
circle lies in 1st and 2nd quadrant

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1 Answer

  1. This answer was edited.

    Using the mid point formula coordinates of mid points are

     

    (x1 + x2) / 2 = X

    (y1 + y2) / 2 = Y

    Here

    x1 = 6, x2 = -6

    y1 = 3, y2 = 4

     

    ∴ (6 + (-6)) / 2 = 0

    (3 + 4) / 2 = 7/2

    Coordinates of Mid point will be

    (X,Y) = (0,(7/2))

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