ICSE & CBSE Board Question Based on Arithmetic Progression of RS Aggarwal

Here You Have to find the angles with the help of Common Difference in Angle of a Quadrilateral in AP.

This is the Question Number 3 Of Exercise 11 B of RS Aggarwal Solution.

# The angles of a quadrilateral are in AP whose common difference is 10°. Find the angles.

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Since the angles are in A.P., let the angles are p, p+10, p+20, p+30

sum of angles=360

⇒ p + p+10 + p+20 + p+30 = 360

⇒ 4p + 60 = 360

⇒ 4p = 360-60 = 300

⇒ p = 300/4 = 75

So the angles are

p = 75

p+10 = 75+10 = 85

p+20 = 75+20 = 95

p+30 = 75+30 = 105

75,85,95,105