ICSE & CBSE Board Question Based on Arithmetic Progression of RS Aggarwal
Here You Have to find the angles with the help of Common Difference in Angle of a Quadrilateral in AP.
This is the Question Number 3 Of Exercise 11 B of RS Aggarwal Solution.
Deepak BoraNewbie
The angles of a quadrilateral are in AP whose common difference is 10°. Find the angles.
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Since the angles are in A.P., let the angles are p, p+10, p+20, p+30
sum of angles=360
⇒ p + p+10 + p+20 + p+30 = 360
⇒ 4p + 60 = 360
⇒ 4p = 360-60 = 300
⇒ p = 300/4 = 75
So the angles are
p = 75
p+10 = 75+10 = 85
p+20 = 75+20 = 95
p+30 = 75+30 = 105
75,85,95,105