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deepaksoni
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Asked: 2021-03-16T23:20:53+05:30 In:

The age of a man is twice the square of the age of his son. Eight years hence, the age of the man will be 4 years more than three times the age of his son. Find the present age.

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This question has been taken from Book:- ML aggarwal, Avichal publication, class10th, quadratic equation in one variable, chapter 5, exercise 5.5
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The age of a man is twice the square of the age of his son.

Eight years hence, the age of the man will be 4 years more than three times the age of his son. Find the present age.
Question no43. , ML Aggarwal, chapter 5, exercise 5.5, quadratic equation in one variable, ICSE board,

icse boardml aggarwal solutionquadratic equation in one variable
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    1. Guru

      Solution:
      Let the present age of the son = x years
      then, the present age of the man = 2x² years.
      8 years hence,
      The age of son will be = (x + 8) years and the
      age of man = (2x² + 8) years
      According to the problem,
      ML Aggarwal Class 10 Solutions for ICSE Maths Chapter 5 Quadratic Equations in One Variable Ex 5.5 Q43.1

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