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Deepak Bora
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The 7th term of an AP is -4 and its 13th term is -16 Find the AP.

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This is the Important question based on Arithmetic progression Chapter of R.S Aggarwal book for ICSE & CBSE
Board.
Here the 2 terms of AP is given. you have to find the first term, common difference and the AP
This is the Question Number 16 Exercise 11 A of RS Aggarwal Solution.

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  1. Let us say a be the first term and d be the common difference of an AP

    an = a + (n – 1)d

    a7 = a + (7 – 1)d

    = a + 6d = -4 …………(1)

    And a13 = a + 12d = -16 …..…..(2)

    Subtracting equation (1) from (2), we get

    6d = -16 – (-4) = -12

    From (1), a + 6d = -4

    a + (-12) = -4

    a = -4 + 12 = 8

    a = 8, d = -2

    AP will be 8, 6, 4, 2, 0, ……

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