The question is given from ncert Book of class 10th Chapter no. 5 Ex. 5.3 Q. 1 (i). In the following question you have to find the sum of the Arithmetic Progression given above. Give the solution of the above question in brief.
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Given, 2, 7, 12 ,…, to 10 terms
For this A.P.,
first term, a = 2
And common difference, d = a2 − a1 = 7−2 = 5
n = 10
We know that, the formula for sum of nth term in AP series is,
Sn = n/2 [2a +(n-1)d]
S10 = 10/2 [2(2)+(10 -1)×5]
= 5[4+(9)×(5)]
= 5 × 49 = 245