An important and exam oriented question from quadratic equation chapter as it was already asked in various examinations in which we have to solve the given equation 48x²-13x-1=0
Kindly solve the above problem in detail
RS Aggarwal, Class 10, chapter 4A, question no 19
48x²-13x−1=0
48x²−(16x−3x)−1=0
48x²−16x+3x−1=0
16x(3x−1)+1(3x−1)=0
(16x+1)(3x−1)=0
Either 16x+1=0 or 3x−1=0
x=−1/16 or 1/3