This question is taken from quadratic equation chapter in which we have been asked to solve the equation 15x²-20=x
Kindly solve the above problem in detail
RS Aggarwal, Class 10, chapter 4A, question no 17
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15x²−28=x
15x²−x−28=0
15x²−(21x−20x)28=0
15x²−21x+20x−28=0
3x(5x−7)+4(5x−7)=0
(3x+4)(5x−7)=0
3x+4=0 or 5x−7=0
x=−4/3 or 7/5