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Rajan@2021
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Solve the following quadratic equation: 15x²-28=x

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This question is taken from quadratic equation chapter in which we have been asked to solve the equation 15x²-20=x

Kindly solve the above problem in detail

RS Aggarwal, Class 10, chapter 4A, question no 17

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1 Answer

  1. 1528=x

    15x28=0

    15(21x20x)28=0

    1521x+20x28=0

    3x(5x7)+4(5x7)=0

    (3x+4)(5x7)=0

    3x+4=0 or 5x7=0

    x=4/3 or 7/5

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